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Question Number 102581 by bemath last updated on 10/Jul/20

$$Ifx+iy=3+2xi$$$$.findy$$

Answered by bemath last updated on 10/Jul/20

Answered by Rasheed.Sindhi last updated on 10/Jul/20

$$x+iy=3+2xi$$$$x=3\wedge y=2x$$$$y=2x=2\left(3\right)=6\underset{⌣}{\stackrel{⌢}{\bullet }}\stackrel{⌢}{\bullet }$$

Commented by bemath last updated on 10/Jul/20

$$\stackrel{⌢\bullet ⌢}{⌣}$$

Commented by 1549442205 last updated on 10/Jul/20

$$\mathrm{if}\mathrm{given}\mathrm{x},\mathrm{y}\mathrm{are}\mathrm{real}\mathrm{then}\mathrm{the}\mathrm{case}{\mathrm{x}}^2=\frac{-9}{4}$$$$\mathrm{need}\mathrm{rejected}\mathrm{and}\mathrm{y}=6\mathrm{is}\mathrm{unique}\mathrm{root}$$

Commented by bemath last updated on 10/Jul/20

$$yes...agree$$

Answered by Dwaipayan Shikari last updated on 10/Jul/20

$$x+iy=3+2xi$$$$y=2xx=3$$$$soy=2.3=6\ddots \text{iddots}\ddots \text{iddots}\ddots \text{iddots}⋮\dots ⋮\dots ⋮\dots$$

Answered by mathmax by abdo last updated on 10/Jul/20

$$(1,\mathrm{i})\mathrm{is}\mathrm{a}\mathrm{base}\mathrm{so}\mathrm{x}+\mathrm{iy}=3+2\mathrm{xi}\Rightarrow \mathrm{x}=3\mathrm{and}\mathrm{y}=2\mathrm{x}\Rightarrow \mathrm{x}=3\mathrm{and}\mathrm{y}=6$$

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