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Question Number 102635 by ketto255 last updated on 10/Jul/20
Answered by bobhans last updated on 10/Jul/20
sin(90o−θ)=cosθ=±1−sin2θ=±1−225=±235
Answered by Rasheed.Sindhi last updated on 10/Jul/20
sin(90−θ)=cosθsin2θ+cos2θ=1(25)2+cos2θ=1cosθ=±1−225=±235sin(90−θ)=±235★
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