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Question Number 102638 by bemath last updated on 10/Jul/20

$$toMrW$$$$iforgottheformulatofind$$$$theareaofatriangleby$$$$usingthethreeheightline$$

Commented by Ar Brandon last updated on 10/Jul/20

$$Permitmetointervain$$$$\mathrm{Maybe}\mathrm{you}\mathrm{should}\mathrm{just}\mathrm{search}\mathbf{triangle}.$$$$\mathrm{It}\mathrm{is}\mathrm{possible}\mathrm{with}\mathrm{the}\mathrm{recent}\mathrm{update}.$$

Commented by bemath last updated on 10/Jul/20

$$howsir?$$

Commented by mr W last updated on 10/Jul/20

$$doyoumeanQ97236?$$

Commented by bemath last updated on 10/Jul/20

$$yessir.thankyou$$$$$$

Commented by Ar Brandon last updated on 10/Jul/20

I meant in "search question"��

Commented by bemath last updated on 10/Jul/20

������

Answered by bramlex last updated on 10/Jul/20

$$\mathrm{area}=\frac{1}{\sqrt{(\frac{1}{{\mathrm{h}}_1}+\frac{1}{{\mathrm{h}}_2}+\frac{1}{{\mathrm{h}}_3})(-\frac{1}{{\mathrm{h}}_1}+\frac{1}{{\mathrm{h}}_2}+\frac{1}{{\mathrm{h}}_3})(\frac{1}{{\mathrm{h}}_1}-\frac{1}{{\mathrm{h}}_2}+\frac{1}{{\mathrm{h}}_3})(\frac{1}{{\mathrm{h}}_1}+\frac{1}{{\mathrm{h}}_2}-\frac{1}{{\mathrm{h}}_3})}}$$

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