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Question Number 102642 by otchereabdullai@gmail.com last updated on 10/Jul/20

Answered by som(math1967) last updated on 10/Jul/20

∠SRQ=∠RTS=28  x=180−∠VRS=∠VRM+∠SRQ  =46+28=74°ans

SRQ=RTS=28x=180VRS=VRM+SRQ=46+28=74°ans

Commented by bemath last updated on 10/Jul/20

sir, why ∠SRQ = ∠RTS

sir,whySRQ=RTS

Commented by som(math1967) last updated on 10/Jul/20

Angles in alternate segment

Anglesinalternatesegment

Commented by som(math1967) last updated on 10/Jul/20

let O is centre  ∴∠ORS=∠OSR [OR=OS]  ∠ORS=90−(1/2)∠ROS  ∠ORS=90−∠RTS  ∴∠RTS=90−∠ORS  Again ∠SRQ=90−∠ORS  [∵OR radd. RQ tanjent]  ∴∠RTS=∠SRQ

letOiscentreORS=OSR[OR=OS]ORS=9012ROSORS=90RTSRTS=90ORSAgainSRQ=90ORS[ORradd.RQtanjent]RTS=SRQ

Commented by som(math1967) last updated on 10/Jul/20

Commented by otchereabdullai@gmail.com last updated on 10/Jul/20

thanks a lot sir! i appreciate your time

thanksalotsir!iappreciateyourtime

Answered by bramlex last updated on 10/Jul/20

x = (1/2)(92^o +56^o ) = 74^o

x=12(92o+56o)=74o

Commented by bramlex last updated on 10/Jul/20

Commented by otchereabdullai@gmail.com last updated on 10/Jul/20

wow !

wow!

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