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Question Number 102796 by saorey0202 last updated on 11/Jul/20
Theanglebetweenthevectors2i+3j+kand2i−j−kis
Answered by bramlex last updated on 11/Jul/20
cosβ=a→.b→∣a→∣∣b→∣=4−3−1∣a→∣∣b→∣β=90o
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