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Question Number 1030 by 123456 last updated on 20/May/15
dydt−dxdt=tdydt+ytdxdt+x
Answered by prakash jain last updated on 21/May/15
y=k1t,x=k2tdydt=k1,dxdt=k2k1−k2=k1t+k1tk2t+k2t=k1k2k1−k2=k1k2k22−k1k2+k1=0k2=k1±k12−4k12k12−4k1⩾0⇒k1(k1−4)⩾0⇒k1⩽0∨k1⩾4
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