{ ((x^2 +2xy+21=6x)),((y^2 +2yz−8=6y)),((z^2 +2zx−4=6z)) :} find x+y+z


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Question Number 103043 by bemath last updated on 12/Jul/20
${ ((x^2 +2xy+21=6x)),((y^2 +2yz−8=6y)),((z^2 +2zx−4=6z)) :} find x+y+z$
${\begin{cases} x^{2} + 2 x y + 21 = 6 x \\ y^{2} + 2 y z - 8 = 6 y \\ z^{2} + 2 z x - 4 = 6 z \end{cases}$ $f i n d x + y + z$
	Answered by maths mind last updated on 12/Jul/20

	$\Rightarrow {(x + y + z)}^{2} - 6 (x + y + z) + 9 = 0$
	Commented by bemath last updated on 12/Jul/20
	coll ,��
	Commented by Rasheed.Sindhi last updated on 12/Jul/20

	$N i c e!$
	Answered by Dwaipayan Shikari last updated on 12/Jul/20

	${(x + y + z)}^{2} - 6 (x + y + z) + 9 = 0$ $x + y + z = 3$
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