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Question Number 10317 by Tawakalitu ayo mi last updated on 03/Feb/17
Solveforx.32x=18xpleaseineedworkings.
Answered by mrW1 last updated on 03/Feb/17
(32)x=18x9x=18xexln9=18x1=18−ln9(−xln9)e−xln9(−xln9)e−xln9=−ln918−xln9=W(−ln918)withW=LambertWfunctionx=−W(−ln918)ln9=−W(−0.122068)2.197225={−−0.1404792.197225=0.063935−−3.2958372.197225=1.5
Commented by Tawakalitu ayo mi last updated on 04/Feb/17
Godblessyousir.
Answered by arge last updated on 04/Feb/17
log32x=log18x2xlog3=log18+logxlogx=y0.95x=1.26+yx=1.26+y0.95
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