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Question Number 103422 by aurpeyz last updated on 15/Jul/20

Commented by Worm_Tail last updated on 15/Jul/20

$$distancemovedbycar=60t$$$$distancemovedbyA=40t$$$$distancemovedbyB=40t$$$$totaldistancemovedbycarandB=50=100t$$$$\Rightarrow t=\frac{1}{2}$$$$d_{car}=60\times 0.5=30km{d}_A=40\times 0.5=20km$$$$dcar-d_A=10km$$$$$$$$$$

Commented by aurpeyz last updated on 15/Jul/20

$$\mathrm{thanks}\mathrm{sir}$$

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