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Question Number 103448 by aurpeyz last updated on 15/Jul/20

Answered by Worm_Tail last updated on 15/Jul/20

$$u_x=30cos40=22.981m.s^{-1}{s}_x=28$$$$s_x=u_{x}t\Rightarrow t=\frac{28}{22.981}=1.2184$$$$s_y=\left(30sin40\right)-\frac{1}{2}\left(10\right){(1.2184)}^2$$$$s_y=11.8611m$$

Commented by aurpeyz last updated on 15/Jul/20

$$\mathrm{thanks}\mathrm{sir}$$

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