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Question Number 103481 by mohammad17 last updated on 15/Jul/20

prove that (cos((nθ)/5)+isin((2nθ)/(10)))^5 −(1/e^(inθ) )=2sin(nθ) ?

provethat(cosnθ5+isin2nθ10)51einθ=2sin(nθ)?

Answered by Dwaipayan Shikari last updated on 15/Jul/20

e^(nθi) −e^(−inθ) =2sin(nθ)  (e^(((nθ)/5)i) )^5 =e^(nθi)      {cosnθ+isinnθ−cosnθ+isinnθ=2isinnθ

enθieinθ=2sin(nθ)(enθ5i)5=enθi{cosnθ+isinnθcosnθ+isinnθ=2isinnθ

Commented by mohammad17 last updated on 15/Jul/20

thank you sir

thankyousir

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