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Question Number 103582 by aurpeyz last updated on 15/Jul/20
Commented by mr W last updated on 16/Jul/20
nouniquesolutionpossible!
T1cosα−T2cosβ=0T1sinα+T2sinβ=(10+25)g=350⇒T1=350cosβsin(α+β)⇒T2=350cosαsin(α+β)thatmeansyoucangetanyvalueforT1andT2byselectingcertainαandβ.
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