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Question Number 103585 by aurpeyz last updated on 15/Jul/20

Answered by Worm_Tail last updated on 16/Jul/20

CW=ACW     (430×9.8×2.5)+(85×9.8×((√(1.67^2 +2.5^2 ))/2)sin(tan^(−1) ((2.5)/(1.67))))=T(1.67)     (10535)+(1041.25)=T(1.67)     11576.25=T(1.67)  T=((11576.25)/(1.67))=6931.886288N

CW=ACW(430×9.8×2.5)+(85×9.8×1.672+2.522sin(tan12.51.67))=T(1.67)(10535)+(1041.25)=T(1.67)11576.25=T(1.67)T=11576.251.67=6931.886288N

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