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Question Number 103620 by bobhans last updated on 16/Jul/20
Ifa2−bc,b2−ac,c2−abisAPwherea+c=12,findthevalueofa+b+c
Answered by bemath last updated on 16/Jul/20
⇒AP:2(b2−ac)=a2−bc+c2−ab2b2−2ac=a2+c2−ab−bc2b2−2ac=(a+c)2−2ac−ab−bc2b2=144−ab−b(12−a)2b2=144−12bb2+6b−72=0⇒(b+12)(b−6)=0→{b=6b=−12∴a+b+c=18orzero
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