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Question Number 103781 by abony1303 last updated on 17/Jul/20

Commented by abony1303 last updated on 17/Jul/20

pls help ASAP

$$\mathrm{pls}\:\mathrm{help}\:\mathrm{ASAP} \\ $$

Commented by bemath last updated on 17/Jul/20

2^(100)

$$\mathrm{2}^{\mathrm{100}} \\ $$

Commented by abony1303 last updated on 17/Jul/20

how ser? Please, can you explain

$$\mathrm{how}\:\mathrm{ser}?\:\mathrm{Please},\:\mathrm{can}\:\mathrm{you}\:\mathrm{explain} \\ $$

Commented by mr W last updated on 17/Jul/20

put x=1 into the equation, you get  (1+1)^(100) =a_0 +a_1 ×1+a_2 ×1^2 +...+a_(100) ×1^(100)   ⇒2^(100) =a_0 +a_1 +a_2 +...+a_(100)

$${put}\:{x}=\mathrm{1}\:{into}\:{the}\:{equation},\:{you}\:{get} \\ $$$$\left(\mathrm{1}+\mathrm{1}\right)^{\mathrm{100}} ={a}_{\mathrm{0}} +{a}_{\mathrm{1}} ×\mathrm{1}+{a}_{\mathrm{2}} ×\mathrm{1}^{\mathrm{2}} +...+{a}_{\mathrm{100}} ×\mathrm{1}^{\mathrm{100}} \\ $$$$\Rightarrow\mathrm{2}^{\mathrm{100}} ={a}_{\mathrm{0}} +{a}_{\mathrm{1}} +{a}_{\mathrm{2}} +...+{a}_{\mathrm{100}} \\ $$

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