Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 10387 by FilupSmith last updated on 06/Feb/17

$$6\mathrm{people}a,b,c,d,e,\mathrm{and}f\mathrm{stand}\mathrm{in}\mathrm{a}\mathrm{line}.$$$$$$$$\mathrm{The}\mathrm{number}\mathrm{of}\mathrm{ways}\mathrm{they}\mathrm{can}\mathrm{stand}\mathrm{arranged}$$$$\mathrm{is}\mathrm{equal}\mathrm{to}6!$$$$$$$$\mathrm{If}\mathrm{two}\mathrm{people}\mathrm{have}\mathrm{to}\mathrm{stand}\mathrm{next}\mathrm{to}\mathrm{each}\mathrm{other},$$$$\mathrm{but}\mathrm{everyone}\mathrm{else}\mathrm{do}\mathrm{not}\mathrm{matter},\mathrm{how}\mathrm{many}\mathrm{combinations}$$$$\mathrm{combinations}\mathrm{are}\mathrm{there}?$$$$$$$$\mathrm{e}.\mathrm{g}.\left(ab\right)cdef\mathrm{or}cd\left(ba\right)ef$$

Answered by sandy_suhendra last updated on 06/Feb/17

$$\mathrm{the}\mathrm{two}\mathrm{people}\mathrm{we}\mathrm{assume}\mathrm{as}1\mathrm{people}$$$$\mathrm{so}\mathrm{there}\mathrm{are}5\mathrm{people}\Rightarrow \mathrm{the}\mathrm{combination}=5!$$$$\mathrm{but}\mathrm{the}\mathrm{two}\mathrm{people}\mathrm{have}\mathrm{combination}=2!$$$$\mathrm{the}\mathrm{total}\mathrm{combination}=2!\times 5!=240$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com