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Question Number 1039 by tera last updated on 22/May/15

jumlah akar−akar persamaan [x]^2 −2[x]−3=0 sama dengan a.−10 b.−3 e.4 c.−1 d.0

jumlahakar−akarpersamaan[x]2−2[x]−3=0samadengana.−10b.−3e.4c.−1d.0

Commented by prakash jain last updated on 22/May/15

[x] =⌊x⌋ =gint(x)?

[x]=⌊x⌋=gint(x)?

Commented by 123456 last updated on 22/May/15

y=[x] y^2 −2y−3=0 Δ=(−2)^2 −4(1)(−3)=4+12=16 y=((−(−2)±(√(16)))/(2(1)))=((2±4)/2)=1±2 y_1 =1−2=−1 y_2 =1+2=+3 [x_1 ]=−1⇔−2≤x_1 ≤−1 [x_2 ]=+3⇔3≤x_2 ≤4

y=[x]y2−2y−3=0Δ=(−2)2−4(1)(−3)=4+12=16y=−(−2)±162(1)=2±42=1±2y1=1−2=−1y2=1+2=+3[x1]=−1⇔−2⩽x1⩽−1[x2]=+3⇔3⩽x2⩽4

Commented by prakash jain last updated on 22/May/15

Please check. ⌊−2⌋=−2 ⌊−1.5⌋=−2 ⌊x⌋=−1⇒−1≤x<0

Pleasecheck.⌊−2⌋=−2⌊−1.5⌋=−2⌊x⌋=−1⇒−1⩽x<0

Commented by 123456 last updated on 23/May/15

what if its is integer part?

whatifitsisintegerpart?

Answered by prakash jain last updated on 22/May/15

Taking [x] as floor function y=⌊x⌋ y^2 −2y−3=0 (y+1)(y−3)=0 y=−1 or y=3 x∈[−1,0)∪[3,4)

Taking[x]asfloorfunctiony=⌊x⌋y2−2y−3=0(y+1)(y−3)=0y=−1ory=3x∈[−1,0)∪[3,4)

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