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Question Number 103928 by I want to learn more last updated on 18/Jul/20

Answered by Dwaipayan Shikari last updated on 18/Jul/20

$$Total$$$$distancetravelinxdirection=\frac{31}{30}km$$$$distancetravelinydirection=\frac{2}{3}km$$$$Netdistancetravelled=\sqrt{{\left(\frac{2}{3}\right)}^2+{\left(\frac{31}{30}\right)}^2}=1.51222222km$$$$Netangle\theta ={tan}^{-1}\frac{20}{31}=32.8285°$$$$$$

Commented by I want to learn more last updated on 18/Jul/20

$$\mathrm{Thanks}\mathrm{sir}$$

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