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Question Number 104141 by bobhans last updated on 19/Jul/20

Answered by bramlex last updated on 19/Jul/20

[ 1 x 2 ] [((2x+2)),(( 2)),(( 1)) ]= 0 ⇒ 2x+2 +2x + 2 = 0 4x = −4 ⇒x = −1

[1x2][2x+221]=0⇒2x+2+2x+2=04x=−4⇒x=−1

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