Question and Answers Forum

All Questions      Topic List

Arithmetic Questions

Previous in All Question      Next in All Question      

Previous in Arithmetic      Next in Arithmetic      

Question Number 104221 by bemath last updated on 20/Jul/20

The diagonals of a  trapezoid ABCD intersect  at point Q lies between the  parallel line BC and AD  such that ∠AQD = ∠CQB ,  line CD separates points P  and Q . Prove that  ∠BQP = ∠DAQ

$${The}\:{diagonals}\:{of}\:{a} \\ $$$${trapezoid}\:{ABCD}\:{intersect} \\ $$$${at}\:{point}\:{Q}\:{lies}\:{between}\:{the} \\ $$$${parallel}\:{line}\:{BC}\:{and}\:{AD} \\ $$$${such}\:{that}\:\angle{AQD}\:=\:\angle{CQB}\:, \\ $$$${line}\:{CD}\:{separates}\:{points}\:{P} \\ $$$${and}\:{Q}\:.\:{Prove}\:{that} \\ $$$$\angle{BQP}\:=\:\angle{DAQ}\: \\ $$

Commented by 1549442205PVT last updated on 20/Jul/20

Question don′t complete,the conditions  isn′t full.So cann′t solve.

$$\mathrm{Question}\:\mathrm{don}'\mathrm{t}\:\mathrm{complete},\mathrm{the}\:\mathrm{conditions} \\ $$$$\mathrm{isn}'\mathrm{t}\:\mathrm{full}.\mathrm{So}\:\mathrm{cann}'\mathrm{t}\:\mathrm{solve}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com