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Question Number 104603 by john santu last updated on 22/Jul/20

$$\underset{x\to -2}{\lim }x\mid x-2\mid$$

Answered by bobhans last updated on 22/Jul/20

$$\underset{x\to -2^{-}}{\lim }x\mid x-2\mid =\underset{x\to -2^{-}}{\lim }x(-x+2)=-8$$$$\underset{x\to -2^{+}}{\lim }x\mid x-2\mid =\underset{x\to -2^{+}}{\lim }x(-x+2)=-8$$

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