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Question Number 1047 by 112358 last updated on 23/May/15

$$Simplifythefollowing$$$$expressionusingthelawsof$$$$Booleanalgebra:$$$$(x\wedge \backsim y)\vee (\backsim y\wedge \backsim z)\vee (\backsim x\wedge \backsim z).$$$$$$

Commented by prakash jain last updated on 24/May/15

$$\backsim x\wedge \backsim z=\backsim (x\vee z)$$$$\backsim y\wedge \backsim z=\backsim (y\vee z)$$$$(\backsim (y\vee z))\vee (\backsim (x\vee z))=\backsim ((y\vee z)\wedge (x\vee z))$$$$=\backsim ((y\wedge x)\vee z)$$$$$$

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