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Question Number 104761 by byaw last updated on 23/Jul/20

$$$$$$\mathrm{A}\mathrm{box}\mathrm{contains}5\mathrm{white}\mathrm{balls},3\mathrm{black}$$$$\mathrm{balls}\mathrm{and}2\mathrm{red}\mathrm{balls}\mathrm{of}\mathrm{the}\mathrm{same}$$$$\mathrm{size}.\mathrm{A}\mathrm{ball}\mathrm{is}\mathrm{selected}\mathrm{at}\mathrm{random}$$$$\mathrm{from}\mathrm{the}\mathrm{box}\mathrm{and}\mathrm{then}\mathrm{replaced}.\mathrm{A}$$$$\mathrm{second}\mathrm{ball}\mathrm{is}\mathrm{then}\mathrm{selected}.\mathrm{Find}$$$$\mathrm{the}\mathrm{probability}\mathrm{of}\mathrm{obtaining}$$$$\mathrm{one}\mathrm{black}\mathrm{ball}\mathrm{or}\mathrm{red}\mathrm{ball}\mathrm{in}\mathrm{any}$$$$\mathrm{order}$$

Commented by mr W last updated on 23/Jul/20

$$2\times \frac{2}{10}\times \frac{3}{10}=\frac{3}{25}$$

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