Question Number 104860 by ~blr237~ last updated on 24/Jul/20
$$\left(\mathrm{1}−{aT}\right)\left(\mathrm{1}−{bT}\right).....\left(\mathrm{1}−{yT}\right)\left(\mathrm{1}−{zT}\right)\:\:\:\:???? \\ $$
Answered by ~blr237~ last updated on 24/Jul/20
$${Just}\:\:{to}\:{smile}\::\:{if}\:{we}\:{remember}\:{the}\:{formula}\:{of}\:{the}\:{frequency}\:\:\:{f}=\frac{\mathrm{1}}{{T}}\:\:{then}\:\:\mathrm{1}−{fT}=\mathrm{0}\: \\ $$$${And}\:{that}\:{product}\:{will}\:{be}\:{null} \\ $$
Commented by 1549442205PVT last updated on 25/Jul/20
$$\mathrm{But}\:\mathrm{you}\:\mathrm{didn}'\mathrm{t}\:\mathrm{give}\:\:\mathrm{a}=\mathrm{b}=...=\mathrm{y}=\mathrm{z}=\mathrm{f}\:\:\mathrm{and} \\ $$$$\mathrm{didn}'\mathrm{t}\:\mathrm{note}\:\mathrm{that}\:\mathrm{f}\:\mathrm{is}\:\mathrm{frequency}\:\mathrm{of}\:\mathrm{light} \\ $$$$\mathrm{wave}.\mathrm{Nobody}\:\mathrm{can}\:\mathrm{guess}\:\mathrm{your}\:\mathrm{idea}!... \\ $$