Miranda did market in 3 day. The monday, she bought 3kg of fish^� ,2kg of meat ,1kg of rice at 10000 $. The wednesday she bought 1kg of fish, 3kg of meat, 2kg of rice at 10000$. And the thursday she bought 4kg of fish, 2kg of meat,3 kg of rice at 12500$. 1) Which price(sum) will spend Miranda if she she go to the market at saturday to buy at the same price 3kg of fish, 1kg of meat and 1.5kg of rice?


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Question Number 105006 by mathocean1 last updated on 25/Jul/20

$M i r a n d a d i d m a r k e t i n 3 d a y .$ $T h e m o n d a y, s h e b o u g h t 3 k g o f f i s \bar{h}$ $, 2 k g o f m e a t, 1 k g o f r i c e a t 10000 $ .$ $T h e w e d n e s d a y s h e b o u g h t 1 k g o f$ $f i s h, 3 k g o f m e a t, 2 k g o f r i c e a t$ $10000 $ .$ $A n d t h e t h u r s d a y s h e b o u g h t 4 k g o f$ $f i s h, 2 k g o f m e a t, 3 k g o f r i c e a t$ $12500 $ .$ $1) W h i c h p r i c e (s u m) w i l l s p e n d M i r a n d a$ $i f s h e s h e g o t o t h e m a r k e t a t$ $s a t u r d a y t o b u y a t t h e s a m e p r i c e$ $3 k g o f f i s h, 1 k g o f m e a t a n d 1.5 k g o f$ $r i c e ?$
	Answered by Rasheed.Sindhi last updated on 25/Jul/20

	$\| \begin{matrix} f & m & r & s u m \\ m o n & 3 & 2 & 1 & 10000 \\ w e d & 1 & 3 & 2 & 10000 \\ t h u & 4 & 2 & 3 & 12500 \\ s a t & 3 & 1 & 1.5 & ? \end{matrix} \|$ $3 x + 2 y + z = 10000$ $x + 3 y + 2 z = 10000$ $4 x + 2 y + 3 z = 12500$ $B y {C r a m e r}^{'} s r u l e$ $x = \frac{{\| \begin{matrix} 10000 & 2 & 1 \\ 10000 & 3 & 2 \\ 12500 & 2 & 3 \end{matrix} \|}_{}}{{\| \begin{matrix} 3 & 2 & 1 \\ 1 & 3 & 2 \\ 4 & 2 & 3 \end{matrix} \|}^{}}$ $y = \frac{{\| \begin{matrix} 2 & 10000 & 1 \\ 3 & 10000 & 2 \\ 2 & 12500 & 3 \end{matrix} \|}_{}}{{\| \begin{matrix} 3 & 2 & 1 \\ 1 & 3 & 2 \\ 4 & 2 & 3 \end{matrix} \|}^{}}$ $z = \frac{{\| \begin{matrix} 2 & 1 & 10000 \\ 3 & 2 & 10000 \\ 2 & 3 & 12500 \end{matrix} \|}_{}}{{\| \begin{matrix} 3 & 2 & 1 \\ 1 & 3 & 2 \\ 4 & 2 & 3 \end{matrix} \|}^{}}$
	Answered by Rasheed.Sindhi last updated on 25/Jul/20

	$3 x + 2 y + z = 10000 . . . . . . . . . (i)$ $x + 3 y + 2 z = 10000 . . . . . . . . . (i i)$ $4 x + 2 y + 3 z = 12500 . . . . . . . . . (i i i)$ $(i) - (i i) : 2 x - y - z = 0 \Rightarrow z = 2 x - y$ $^{★} (i) \Rightarrow 3 x + 2 y + (2 x - y) = 10000$ $\Rightarrow 5 x + y = 10000 . . . . . . . . . (i v)$ $^{★} (i i) \Rightarrow x + 3 y + 2 (2 x - y) = 10000$ $\Rightarrow 5 x + y = 10000$ $^{★} (i i i) \Rightarrow 4 x + 2 y + 3 (2 x - y) = 12500$ $\Rightarrow 10 x - y = 12500 . . . . . . . . (v)$ $(i v) + (v) : 15 x = 22500 \Rightarrow x = 1500 $$ $5 x + y = 10000 \Rightarrow y = 10000 - 5 (1500)$ $y = 2500 $$ $(i) \Rightarrow z = 10000 - 3 x - 2 y$ $(i) \Rightarrow$ $z = 10000 - 3 (1500) - 2 (2500)$ $z = 500 $$ $Conclusion : A l l t h i n g s a r e v e r y$ $e x p e n s i v e i n m a t h o c e a n 1^{'} s$ $c o u n t r y .$
	Commented by mathocean1 last updated on 25/Jul/20

	$h a h a h a h a n o t t o o e x p e n s i v e . . .$ $I t i s t h e p r o b l e m o f c u r r e n c y ($ i n s t e a d o f X A F) .$ $T h a n k y o u s i r .$
	Commented by Rasheed.Sindhi last updated on 26/Jul/20

	$h a h a h a h a . . . . . . A m u s i n g$ $i n f o r m a t i o n I r e c e i v e d (t h r o u g h$ $i n t e r n e t!) I w a s t o t a l l y u n a w a r e o f t h e c u r r e n c y$ $o f y o u r c o u n t r y (X A F) . . . .$ $A n y w a y y o u h a v e i n c r e a s e d$ $y o u r e x p e n c e s b y u s i n g $ s i g n :)$
	Commented by mathocean1 last updated on 25/Jul/20

	$E x a c t l y s i r!$
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