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Question Number 105057 by I want to learn more last updated on 25/Jul/20

	Answered by OlafThorendsen last updated on 25/Jul/20

	$\frac{\sqrt{3}}{4} {(2 a)}^{2} - 3 \times \frac{\frac{π}{3}}{2 π} π a^{2}$ $= (\sqrt{3} - \frac{π}{2}) a^{2} (4)$
	Commented by I want to learn more last updated on 25/Jul/20

	$Thanks sir .$
	Answered by Dwaipayan Shikari last updated on 25/Jul/20

	$A r e a o f t h e t r i a n g l e b e t w e e n t h e s e p o i n t s = \frac{1}{2} . \frac{\sqrt{3}}{2} 4 a^{2} {c m}^{2}$ $I t i s a e q u i l a t e r a l t r i n g l e w i t h^{'} 2 a^{'} c m e a c h s i d e$ $A n g l e b e t w e e n p o i n t s = 60 °$ $S o a r e a n e s t e d b y t h e 3 s e m i c i r c l e s a r e 3 (\frac{60 °}{360 °} \times π a^{2}) = \frac{π a^{2}}{2} {c m}^{2}$ $A r e a o f t h e s h a d e d r e g i o n = (\sqrt{3} a^{2} - \frac{π a^{2}}{2}) = (\frac{2 \sqrt{3} - π}{2}) a^{2} {c m}^{2}$
	Commented by I want to learn more last updated on 25/Jul/20

	$Thanks sir$
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