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Question Number 105076 by ajfour last updated on 25/Jul/20

Commented by ajfour last updated on 26/Jul/20

$L e t f r i c t i o n c o e f f i c i e n t b e t w e e n$ $g r o u n d a n d b o t h s e m i - c y l i n d e r s$ $b e μ g i v e n . F i n d α a n d f r i c t i o n$ $c o e f f i c i e n t b e t w e e n b o t h s e m i -$ $c y l i n d r i c a l s u r f a c e s (η) i f b o t h$ $s e m i - c y l i n d e r s a r e o n t h e v e r g e$ $o f s l i p p i n g .$
	Answered by ajfour last updated on 26/Jul/20

	Answered by mr W last updated on 26/Jul/20

	Commented by ajfour last updated on 27/Jul/20

	$b u t i h a v e e d i t e d t h e q u e s t i o n,$ $S i r . . .$
	Commented by mr W last updated on 26/Jul/20

	$e = \frac{4 r}{3 π}$ $\tan ϕ = μ$ $\tan δ = η$ $γ = α - δ$ $\frac{R_{2}}{\sin ϕ} = \frac{M g}{\sin (γ + ϕ)}$ $\Rightarrow R_{2} = \frac{M g \sin ϕ}{\sin (α - δ + ϕ)}$ $\frac{R_{2}}{\sin ϕ} = \frac{M g}{\sin (γ - ϕ)}$ $\Rightarrow R_{2} = \frac{M g \sin ϕ}{\sin (α - δ - ϕ)}$ $\Rightarrow \sin (α - δ + ϕ) = \sin (α - δ - ϕ)$ $. . . s e e m s i m p o s s i b l e . . .$
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