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Question Number 105080 by 175mohamed last updated on 25/Jul/20

$$solve:$$$$x((x^2-1)!)=5((x-1)!)$$

Answered by JDamian last updated on 25/Jul/20

$$\mathit{x}\cdot x((x^2-1)!)=\mathit{x}\cdot 5((x-1)!)$$$$x^2((x^2-1)!)=5x((x-1)!)$$$$\left(x^2\right)!=5\cdot x!$$$$$$

Answered by OlafThorendsen last updated on 25/Jul/20

$$x\mathrm{\Gamma }\left(x^2\right)=5\mathrm{\Gamma }\left(x\right)$$$$x^2\mathrm{\Gamma }\left(x^2\right)=5x\mathrm{\Gamma }\left(x\right)$$$$\mathrm{\Gamma }(x^2+1)=5\mathrm{\Gamma }(x+1)$$$$\mathrm{no}\mathrm{solution}\mathrm{in}\mathbb{C}$$

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