99−98((98)/(99)) = ? Can you solve this?


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Question Number 105207 by Anindita last updated on 26/Jul/20

$99 - 98 \frac{98}{99} = ?$ $C a n y o u s o l v e t h i s ?$
Commented by qwerty111 last updated on 26/Jul/20

$98 + \frac{99}{99} - 98 - \frac{98}{99} = \frac{1}{99}$
Commented by JDamian last updated on 26/Jul/20

$d o y o u a s s u m e a \frac{b}{c} m e a n s a + \frac{b}{c} ?$
Commented by JDamian last updated on 27/Jul/20

$I n e v e r u s e d / u n d e r s t o o d a \frac{b}{c} = a + \frac{b}{c} i n$ $a l g e b r a / m a t h s t e x t s . I o n l y f o u n d i n, f o r$ $i n s t a n c e, c o o k i n g r e c i p e s b o o k s (‘ ‘ 2 1 / 2$ ${t e a s p o o n}^{″})$
	Answered by Aziztisffola last updated on 26/Jul/20

	$99 \frac{99}{99} - 98 \frac{98}{99} = 99 \frac{98 + 1}{99} - 98 \frac{98}{99}$ $= (98 + 1) \frac{98 + 1}{99} - 98 \frac{98}{99} = 98 \frac{98}{99} + \frac{2 \times 98}{99} + \frac{1}{99} - 98 \frac{98}{99}$ $= \frac{2 \times 98 + 1}{99} = \frac{196}{99}$
	Commented by Aziztisffola last updated on 27/Jul/20

	$I know that a + \frac{b}{c} \neq a \times \frac{b}{c}$ $ax = a \times x not a + x .$
	Commented by PRITHWISH SEN 2 last updated on 27/Jul/20

	$98 \times \frac{98}{99} + \frac{2 \times 98}{99} + \frac{1}{99} - 98 \frac{98}{99} \neq \frac{2 \times 98 + 1}{99}$ $as 98 \times \frac{98}{99} \neq 98 \frac{98}{99}$
	Commented by PRITHWISH SEN 2 last updated on 27/Jul/20

	$2 \frac{1}{3} = \frac{7}{3}$ $2 \frac{1}{3} = 2 + \frac{1}{3} = \frac{7}{3}$ $2 \frac{1}{3} = 2 \times \frac{1}{3} = \frac{2}{3}$ $∴ 2 \frac{1}{3} = 2 + \frac{1}{3} \neq 2 \times \frac{1}{3}$ $∴ you are wrong$
	Commented by qwerty111 last updated on 26/Jul/20

	$★ 98 \frac{98 + 1}{99} ★$
	Commented by Aziztisffola last updated on 26/Jul/20

	$Just a simple calculus .$
	Commented by qwerty111 last updated on 26/Jul/20

	$O k$
	Commented by Aziztisffola last updated on 26/Jul/20

	$I assume a \frac{b}{c} = a \times \frac{b}{c} not a + \frac{b}{c}$
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