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Question Number 105239 by bemath last updated on 27/Jul/20
∑∑11p=8p∑6p=5p∫1311(12kyx2+6x)dx=∑∑12p=9p∑7p=4p∫1611(x2y−32k)dxsolvefory
Answered by john santu last updated on 27/Jul/20
(1)∑6p=5p=11(2)∑11p=8p=38(3)∑7p=4p=22(4)∑12p=9p=42⇔∑3811∫1311(12kx−2y+6x)dx=∑3811[(−12kyx+3x2)]1113=∑3811(3(48)+12ky(111−113))thestrangequestion.
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