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Question Number 105278 by Anindita last updated on 27/Jul/20

$$(1-\frac{1}{1})(1-\frac{1}{2})(1-\frac{1}{3}).....(1-\frac{1}{100})=?$$

Commented by bshahid010@gmail.com last updated on 27/Jul/20

$$\mathrm{Its}\mathrm{answer}\mathrm{will}\mathrm{be}0$$$$\mathrm{as}0\times \mathrm{x}\mathrm{x}\in \mathrm{R}\mathrm{is}0$$

Answered by nimnim last updated on 27/Jul/20

$$Sol:(1-\frac{1}{1})(1-\frac{1}{2})(1-\frac{1}{3}).....(1-\frac{1}{100})$$$$=\left(0\right)(1-\frac{1}{2})(1-\frac{1}{3}).....(1-\frac{1}{100})$$$$=0$$$$$$

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