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Question Number 105289 by Anindita last updated on 27/Jul/20

$$\sqrt{52}+\sqrt{3}-\sqrt{\frac{4}{6}}=?$$

Answered by SUMIT007 last updated on 27/Jul/20

$$\Rightarrow 2\sqrt{13}+\sqrt{3}-\sqrt{\frac{2}{3}}$$$$\Rightarrow 2\sqrt{13}+\sqrt{3}-\frac{\sqrt{6}}{3}$$$$\Rightarrow \frac{6\sqrt{13}+3\sqrt{3}-\sqrt{6}}{3}$$$$\Rightarrow \frac{6\times 3.6+3\times 1.7-1.41\times 1.7}{3}$$$$(\sqrt{6}=3.6\sqrt{3}=1.7\sqrt{2}=1.41)$$$$\Rightarrow 6\times 1.2+1.7-.47\times 1.7$$$$\Rightarrow 7.2+1.7-.8$$$$\Rightarrow 8.1$$

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