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Question Number 105929 by Study last updated on 01/Aug/20
Answered by Dwaipayan Shikari last updated on 01/Aug/20
limx→2ddx(xxx)+xx(logx+1)+4x3+2x+12x=xxx(xxx+xx(logx+1)logx)+xx(logx+1)+4x3+2x+12x=222(2+4(log2+1)log2)+4(log2+1)+32+4+14=4(2+4(log2)2+4log2)+log2+414xxx=yxxlogx=logyxx.1x+xx(logx+1)logx=1y.dydxxxx(xxx+xx(logx+1)logx)=dydx{ddx(xx)=xx(1+logx)
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