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Question Number 106237 by Study last updated on 03/Aug/20

Answered by Dwaipayan Shikari last updated on 03/Aug/20

$$\frac{1}{n}\underset{n\to \mathrm{\infty }}{\lim }(e^{\frac{1}{n}}+e^{\frac{2}{n}}+....+e^{\frac{n}{n}})$$$$\frac{1}{n}\underset{n\to \mathrm{\infty }}{\lim }\underset{r=1}{\sum ^n}{e}^{\frac{r}{n}}$$$${\int }_0^1{e}^{x}dx=e-1$$

Commented by mohammad17 last updated on 03/Aug/20

$$canyouexactilyghissir?$$

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