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Question Number 106314 by Study last updated on 04/Aug/20

Answered by bemath last updated on 04/Aug/20

GP ⇒S = (1/(1−(−1))) = (1/2)  1+1.(−1)+1(−1)^2 +1(−1)^3 +...

GPS=11(1)=121+1.(1)+1(1)2+1(1)3+...

Commented by Study last updated on 04/Aug/20

∣q∣=1 for this form we have s_∞ =((a(q^n −1)/(q−1))

q∣=1forthisformwehaves=a(qn1q1

Answered by Dwaipayan Shikari last updated on 04/Aug/20

S=1+x+x^2 +x^3 +x^4 +x^5 +x^6 +x^7 +...  S=(1/(1−x))  S=1−1+1−1+1−1+1−1+1−1+1−1+...  =(1/(1+1))=(1/2)  It is  a Mean of the probable value

S=1+x+x2+x3+x4+x5+x6+x7+...S=11xS=11+11+11+11+11+11+...=11+1=12ItisaMeanoftheprobablevalue

Answered by Her_Majesty last updated on 04/Aug/20

sum doesn′t exist

sumdoesntexist

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