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Question Number 106314 by Study last updated on 04/Aug/20

Answered by bemath last updated on 04/Aug/20

$$\mathrm{GP}\Rightarrow \mathrm{S}=\frac{1}{1-(-1)}=\frac{1}{2}$$$$1+1.(-1)+1{(-1)}^2+1{(-1)}^3+...$$

Commented by Study last updated on 04/Aug/20

$$\mid q\mid =1forthisformwehave{s}_{\mathrm{\infty }}=\frac{a(q^n-1}{q-1}$$

Answered by Dwaipayan Shikari last updated on 04/Aug/20

$$S=1+x+x^2+x^3+x^4+x^5+x^6+x^7+...$$$$S=\frac{1}{1-x}$$$$S=1-1+1-1+1-1+1-1+1-1+1-1+...$$$$=\frac{1}{1+1}=\frac{1}{2}$$$$ItisaMeanoftheprobablevalue$$

Answered by Her_Majesty last updated on 04/Aug/20

$$sum{doesn}^{\prime }texist$$

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