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Question Number 106378 by mr W last updated on 04/Aug/20

Answered by Dwaipayan Shikari last updated on 05/Aug/20

(1−(1/2))(1−(1/4))(1−(1/6))....n  Π_(n=1) ^n (1−(1/(2n)))=y  log(Π_(n=1) ^n (1−(1/(2n))))=logy  Σ_(n=1) ^n log(1−(1/(2n)))=log y  ((Σ_(n=1) ^n log(1−(1/(2n))))/n)≥(Π_(n=1) ^n log(1−(1/(2n))))^(1/n)   ((log((1/2).(3/4)......((2n−1)/(2n))))/n)≥(Π^n log(1−(1/(2n))))^(1/n)

(112)(114)(116)....nnn=1(112n)=ylog(nn=1(112n))=logynn=1log(112n)=logynn=1log(112n)n(nn=1log(112n))1nlog(12.34......2n12n)n(nlog(112n))1n

Commented by mr W last updated on 05/Aug/20

thanks, but it doesn′t answer the  actual question.

thanks,butitdoesntanswertheactualquestion.

Answered by mr W last updated on 05/Aug/20

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