Math Question and Answers


Question and Answers Forum

All Questions Topic List
Arithmetic Questions
Previous in All Question Next in All Question
Previous in Arithmetic Next in Arithmetic
Question Number 106457 by Rio Michael last updated on 05/Aug/20

	Answered by bshahid010 last updated on 05/Aug/20

	$A c c o r d i n g t o q u e s t i o n$ $T_{5} = 50 & T_{7} = 25$ $C o n s i d e r a n A P w i t h i s t t e r m a a n d$ $c o m m o n d i f f e r e n c e d$ $t h e n$ $T_{5} = a + 4 d & T_{7} = a + 6 d$ $a + 4 d = 50 & a + 6 d = 25$ $f r o m a b o v e d = - \frac{25}{2}$ $a n d a = 100$ $N o w T_{15} = a + 14 d = 100 - 175 = - 75$ $a n d S_{20} = \frac{n}{2} (2 a + (n - 1) d)$ $S_{20} = \frac{20}{2} (2 \times 100 - 19 (\frac{25}{2}))$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum