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Question Number 106572 by DeepakMahato last updated on 06/Aug/20

Commented by Rasheed.Sindhi last updated on 06/Aug/20

$\underline{S t i l l a n o t h e r w a y}$ $R o o t s (z e r o s) o f {a x}^{2} + b x + c = 0$ $a r e :$ $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a} = \frac{- b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}$ $I f t h e r o o t s a r e o p p s i t e t o e a c h$ $o t h e r, t h e n \frac{- b}{2 a} = 0$ $S o \frac{- (- 8 k)}{2 (4)} = 0 \Rightarrow k = 0$
Commented by DeepakMahato last updated on 06/Aug/20
Thank You Sir
	Answered by bemath last updated on 06/Aug/20
	$say the roots of polynome is → { (x_1 ),((x_2 =−x_1 )) :} then by Vieta′s rule ⇒x_1 +x_2 =−(b/a) ((8k)/4) = 0 ⇒ k = 0 then f(x) = 4x^2 −9=(2x+3)(2x−3)$
	$say the roots of polynome is \to {\begin{cases} x_{1} \\ x_{2} = - x_{1} \end{cases}$ $then by {Vieta}^{'} s rule \Rightarrow x_{1} + x_{2} = - \frac{b}{a}$ $\frac{8 k}{4} = 0 \Rightarrow k = 0$ $then f (x) = {4 x}^{2} - 9 = (2 x + 3) (2 x - 3)$
	Commented by DeepakMahato last updated on 06/Aug/20
	Thank You Sir��
	Answered by Rasheed.Sindhi last updated on 06/Aug/20

	$\underline{A n O t h e r W a y}$ $4 {(α)}^{2} - 8 k (α) - 9 = 0 = 4 {(- α)}^{2} - 8 k (- α) - 9$ $4 α^{2} - 8 k α - 9 = 4 α^{2} + 8 k α - 9$ $- 8 k = 8 k \Rightarrow k = 0$
	Commented by john santu last updated on 06/Aug/20

	$how to make underline sir ?$
	Commented by Rasheed.Sindhi last updated on 06/Aug/20

	Commented by Rasheed.Sindhi last updated on 06/Aug/20

	$1) S e l e c t t h e t e x t$ $2) P r e s s t h e s h o w n s t r u c t u r e$ $3) C l i c k m i n u s s i g n^{'} -^{'}$
	Commented by john santu last updated on 06/Aug/20

	$thank you sir$
	Commented by Tinku Tara last updated on 06/Aug/20

	$In offline editor there is select$ $and underline option .$
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