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Question Number 10665 by FilupS last updated on 22/Feb/17

$$n\mathrm{th}\mathrm{prime}=p_n$$ $$n\mathrm{th}\mathrm{non}-\mathrm{prime}=q_n$$ $$$$ $$\mathrm{Determine}\mathrm{if}{q}_n>p_n\mathrm{for}\mathrm{\forall }n⩾2$$

Commented byFilupS last updated on 22/Feb/17

$$p_1=2,p_2=3,p_3=5,...$$ $$q_1=1,q_2=4,q_3=6,...$$

Commented bysandy_suhendra last updated on 22/Feb/17

$${\mathrm{p}}_4=7\mathrm{and}{\mathrm{q}}_4=8$$ $${\mathrm{p}}_5=11\mathrm{and}{\mathrm{q}}_5=9\mathrm{but}{\mathrm{q}}_5<{\mathrm{p}}_5$$

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