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Question Number 106743 by mohammad17 last updated on 06/Aug/20

∫(√(secy))dy

$$\int\sqrt{{secy}}{dy} \\ $$

Answered by Sarah85 last updated on 07/Aug/20

∫(√(sec y))dy=∫(dy/(√(cos y)))=∫(dy/(√(1−2sin^2  (y/2))))  let t=(y/2)  2∫(dt/(√(1−2sin^2  t)))=2F (t∣2) =  =2F ((y/2)∣2) +C

$$\int\sqrt{\mathrm{sec}\:{y}}{dy}=\int\frac{{dy}}{\sqrt{\mathrm{cos}\:{y}}}=\int\frac{{dy}}{\sqrt{\mathrm{1}−\mathrm{2sin}^{\mathrm{2}} \:\frac{{y}}{\mathrm{2}}}} \\ $$$$\mathrm{let}\:{t}=\frac{{y}}{\mathrm{2}} \\ $$$$\mathrm{2}\int\frac{{dt}}{\sqrt{\mathrm{1}−\mathrm{2sin}^{\mathrm{2}} \:{t}}}=\mathrm{2}{F}\:\left({t}\mid\mathrm{2}\right)\:= \\ $$$$=\mathrm{2}{F}\:\left(\frac{{y}}{\mathrm{2}}\mid\mathrm{2}\right)\:+{C} \\ $$

Commented by Her_Majesty last updated on 07/Aug/20

you think he′s satisfied with this answer?

$${you}\:{think}\:{he}'{s}\:{satisfied}\:{with}\:{this}\:{answer}? \\ $$

Commented by Sarah85 last updated on 07/Aug/20

not sure, anyway this IS the answer

$$\mathrm{not}\:\mathrm{sure},\:\mathrm{anyway}\:\mathrm{this}\:{IS}\:\mathrm{the}\:\mathrm{answer} \\ $$

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