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Question Number 106810 by Study last updated on 07/Aug/20
limx→0tanx−sinxsinx(cos2x−cosx)=???
Answered by bemath last updated on 07/Aug/20
@bemath@limx→0tanx−sinxsinx(cos2x−cosx)?limx→0tanx(1−cosx)sinx(−2sin(3x2)sin(x2))=limx→0tanx(2sin2(x2)−2sinxsin(3x2)sin(x2)=−1×limx→0tanx.sin(x2)sinxsin(3x2)=−13
Answered by Dwaipayan Shikari last updated on 07/Aug/20
limx→0sinx(1cosx−1)sinx(−2sin3xsinx)limx→02sin2x2cosx−2sin3x2sinx2=limx→02(x2)2cosx−2.3x2.4=−13sinx→x
Answered by 1549442205PVT last updated on 07/Aug/20
limx→0tanx−sinxsinx(cos2x−cosx)=limx→0sinx(1cosx−1)sinx(cos2x−cosx)=limx→01cosx−1cos2x−cosx)=limx→01−cosx2cos2x−cosx−1=limx→01−cosx(cosx−1)(2cosx+1)=limx→0−12cosx+1=−13
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