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Question Number 106997 by Dwaipayan Shikari last updated on 08/Aug/20

Commented by mr W last updated on 08/Aug/20

$$mv-m\times \frac{-v}{2}={\int }_0^{T}fdt=FT$$$$\Rightarrow F=\frac{3mv}{2T}$$

Commented by Dwaipayan Shikari last updated on 08/Aug/20

$${\mathrm{P}}_{\mathrm{f}}-{\mathrm{P}}_{\mathrm{i}}=\int \mathrm{Fdt}$$$$\mid -\frac{\mathrm{mv}}{2}-\mathrm{mv}\mid =\mathrm{FT}$$$$\mathrm{F}=\frac{3\mathrm{mv}}{2\mathrm{T}}$$

Commented by mr W last updated on 08/Aug/20

$$youarerightsir!iforgotthe‘‘{-}^{″}sign.$$

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