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Question Number 107080 by Khalmohmmad last updated on 08/Aug/20
Answered by abdomsup last updated on 08/Aug/20
An=nn{nnn+n2nn+....+1}nn{1nn+(2n)n+(3n)n+....1}An=1nn−1+1nn−2+....+1(1n)n+(2n)n+...+1⇒limn→+∞An=1
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