Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 107092 by 175mohamed last updated on 08/Aug/20

Commented by Dwaipayan Shikari last updated on 08/Aug/20

S=(1/2)

$$\mathrm{S}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$

Commented by hgrocks last updated on 09/Aug/20

����

Answered by Dwaipayan Shikari last updated on 08/Aug/20

First term  (1/6)=((3−2)/(3.2))=(1/2)−(1/3)  second term  ((7−3)/(7.3))=(1/3)−(1/7)  ..((25−7)/(25.7))=(1/7)−(1/(25))  ((121−25)/(25.121))=(1/(25))−(1/(121))  S=(1/2)−(1/3)+(1/3)−(1/7)+(1/7)−(1/(25))+(1/(25))−(1/(121))+...  S=(1/2)          term n→0( n→∞)

$$\mathrm{First}\:\mathrm{term} \\ $$$$\frac{\mathrm{1}}{\mathrm{6}}=\frac{\mathrm{3}−\mathrm{2}}{\mathrm{3}.\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\mathrm{second}\:\mathrm{term} \\ $$$$\frac{\mathrm{7}−\mathrm{3}}{\mathrm{7}.\mathrm{3}}=\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{7}} \\ $$$$..\frac{\mathrm{25}−\mathrm{7}}{\mathrm{25}.\mathrm{7}}=\frac{\mathrm{1}}{\mathrm{7}}−\frac{\mathrm{1}}{\mathrm{25}} \\ $$$$\frac{\mathrm{121}−\mathrm{25}}{\mathrm{25}.\mathrm{121}}=\frac{\mathrm{1}}{\mathrm{25}}−\frac{\mathrm{1}}{\mathrm{121}} \\ $$$$\mathrm{S}=\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{1}}{\mathrm{7}}+\frac{\mathrm{1}}{\mathrm{7}}−\frac{\mathrm{1}}{\mathrm{25}}+\frac{\mathrm{1}}{\mathrm{25}}−\frac{\mathrm{1}}{\mathrm{121}}+... \\ $$$$\mathrm{S}=\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\:\:\:\:\:\:\:\mathrm{term}\:\mathrm{n}\rightarrow\mathrm{0}\left(\:\mathrm{n}\rightarrow\infty\right) \\ $$

Commented by Dwaipayan Shikari last updated on 08/Aug/20

It is just an assumption. Is it right?

$$\mathrm{It}\:\mathrm{is}\:\mathrm{just}\:\mathrm{an}\:\mathrm{assumption}.\:\mathrm{Is}\:\mathrm{it}\:\mathrm{right}? \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com