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Question Number 107521 by otchereabdullai@gmail.com last updated on 11/Aug/20

Answered by bemath last updated on 11/Aug/20

$$\mathrm{\angle }XZY=\frac{1}{2}\times 45°=22.5°$$$$areaofshadedsegment=\frac{1}{8}\pi r^2-\frac{1}{2}{r}^2\sin 45°$$$$=\frac{1}{8}.\frac{22}{7}.49-\frac{1}{2}.49.\frac{1}{2}\sqrt{2}$$$$=49(\frac{11}{28}-\frac{\sqrt{2}}{4})=49\left(\frac{11-7\sqrt{2}}{28}\right)$$$$=\frac{77-49\sqrt{2}}{4}{cm}^2$$

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