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Question Number 107594 by Rio Michael last updated on 11/Aug/20
Findthegreatestcommondivisorof1122and1001andexpressthegreatestcommondivisordintheform.d=1122x+1001yUsingtheaboveresultsolvethecongruenceequation37x≡11(mod33)
Answered by 1549442205PVT last updated on 11/Aug/20
37x−11=33y⇔y=37x−1133=x+4x−1133Set4x−1133=t(t∈Z)⇒4x−11=33t⇔x=33t+114=8t+3+t−14.Sett−14=k⇒t=4k+1(k∈Z)weget{x=33k+11y=37k+12(k∈Z)
Answered by Aziztisffola last updated on 11/Aug/20
wehavegcd(1122;1001)=11=d1122x+1001y=11and37x≡11(mod33)⇔∃k∈Z37x−33k=11⇒37x−33k=11=1122x+1001yUsingGausstheoremwegetx=33k+11
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