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Question Number 107684 by bemath last updated on 12/Aug/20

$$‘‘\mathcal{B}e\mathcal{M}ath‘‘$$$$\ln \tan 1°+\ln \tan 2°+\ln \tan 3°+...+\ln \tan 89°=?$$

Answered by Her_Majesty last updated on 12/Aug/20

$$lntanx°=-lntan(90-x)°$$$$\Rightarrow answerislntan45°=0$$

Commented by bemath last updated on 12/Aug/20

$$thankyouMiss$$

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