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Question Number 107718 by mohammad17 last updated on 12/Aug/20

Answered by Aziztisffola last updated on 12/Aug/20

$$\underset{\mathrm{n}=1}{\sum ^{\mathrm{\infty }}}{\stackrel{-}{\mathrm{z}}}_{\mathrm{n}}=\stackrel{―}{\underset{\mathrm{n}=1}{\sum ^{\mathrm{\infty }}}{\mathrm{z}}_{\mathrm{n}}}=\stackrel{-}{\mathrm{s}}$$

Commented by mohammad17 last updated on 12/Aug/20

$$siriwantdetailsthesolution$$

Commented by Aziztisffola last updated on 12/Aug/20

$$\overline{{\mathrm{z}}_1+{\mathrm{z}}_2}={\stackrel{-}{\mathrm{z}}}_1+{\stackrel{-}{\mathrm{z}}}_2$$$${\stackrel{-}{\mathrm{z}}}_1+{\stackrel{-}{\mathrm{z}}}_2+...+{\stackrel{-}{\mathrm{z}}}_{\mathrm{n}}+...=\overline{{\mathrm{z}}_1+{\mathrm{z}}_2+...+{\mathrm{z}}_{\mathrm{n}}+...}$$$$=\stackrel{-}{\mathrm{s}}$$

Commented by mohammad17 last updated on 12/Aug/20

$$thankyousir$$

Commented by Aziztisffola last updated on 12/Aug/20

$${\mathrm{you}}^{\prime }\mathrm{re}\mathrm{welcome}$$

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