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Question Number 107783 by Dwaipayan Shikari last updated on 12/Aug/20

Σ_(n=1) ^∞ (1/(n2^n ))

∑∞n=11n2n

Commented by Dwaipayan Shikari last updated on 12/Aug/20

(1/(1.2^1 ))+(1/(2.2^2 ))+(1/(3.2^3 ))+(1/(4.2^4 ))+..... =−(−(1/2)−(1/(2.2^2 ))−(1/(3.2^3 ))−...) =−log(1−(1/2)) =log(2)

11.21+12.22+13.23+14.24+.....=−(−12−12.22−13.23−...)=−log(1−12)=log(2)

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