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Question Number 107818 by mathdave last updated on 12/Aug/20

Commented by hgrocks last updated on 12/Aug/20

No It is not correct   For e.g. put x = 2    L.H.S. = ln^2 (3)  R.H.S = ln2.ln(−3)    lhs ≠ rhs

$$\mathrm{No}\:\mathrm{It}\:\mathrm{is}\:\mathrm{not}\:\mathrm{correct}\: \\ $$$$\mathrm{For}\:\mathrm{e}.\mathrm{g}.\:\mathrm{put}\:\mathrm{x}\:=\:\mathrm{2} \\ $$$$ \\ $$$$\mathrm{L}.\mathrm{H}.\mathrm{S}.\:=\:\mathrm{ln}^{\mathrm{2}} \left(\mathrm{3}\right) \\ $$$$\mathrm{R}.\mathrm{H}.\mathrm{S}\:=\:\mathrm{ln2}.\mathrm{ln}\left(−\mathrm{3}\right) \\ $$$$ \\ $$$$\mathrm{lhs}\:\neq\:\mathrm{rhs} \\ $$

Commented by mathdave last updated on 12/Aug/20

ur opinion is needed house

$${ur}\:{opinion}\:{is}\:{needed}\:{house} \\ $$

Commented by mathdave last updated on 12/Aug/20

ur opinion is needed

$${ur}\:{opinion}\:{is}\:{needed} \\ $$

Answered by mathmax by abdo last updated on 13/Aug/20

not correct

$$\mathrm{not}\:\mathrm{correct}\: \\ $$

Answered by Aziztisffola last updated on 13/Aug/20

not correct ,try with some value of x.

$$\mathrm{not}\:\mathrm{correct}\:,\mathrm{try}\:\mathrm{with}\:\mathrm{some}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}. \\ $$

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